Solution Manual Heat And Mass Transfer Cengel 5th Edition Chapter 3 ◎ «PREMIUM»

$Re_{D}=\frac{\rho V D}{\mu}=\frac{999.1 \times 3.5 \times 2}{1.138 \times 10^{-3}}=6.14 \times 10^{6}$

The rate of heat transfer is:

$\dot{Q}=h \pi D L(T_{s}-T

However we are interested to solve problem from the begining

$\dot{Q}_{conv}=150-41.9-0=108.1W$

Solution:

$\dot{Q} {net}=\dot{Q} {conv}+\dot{Q} {rad}+\dot{Q} {evap}$ $Re_{D}=\frac{\rho V D}{\mu}=\frac{999

$h=\frac{Nu_{D}k}{D}=\frac{2152.5 \times 0.597}{2}=643.3W/m^{2}K$

$h=\frac{\dot{Q} {conv}}{A(T {skin}-T_{\infty})}=\frac{108.1}{1.5 \times (32-20)}=3.01W/m^{2}K$ $Re_{D}=\frac{\rho V D}{\mu}=\frac{999

$T_{c}=800+\frac{2000}{4\pi \times 50 \times 0.5}=806.37K$