$$v^2 = u^2 + 2as$$
$$s = \frac{u^2}{2a} = \frac{4^2}{2 \cdot \frac{5}{2}} = \frac{16}{5} m$$ dc pandey physics class 11 pdf download part 1 work
where $W$ is the net work done and $\Delta KE$ is the change in kinetic energy. Let's consider some problems and their solutions: $$v^2 = u^2 + 2as$$ $$s = \frac{u^2}{2a}
Solving for $s$, we get:
Using the formula $W = F \cdot s$, we get: dc pandey physics class 11 pdf download part 1 work